Question on a transverse linear_extrusion from 2d *.dxf file

Hello,

after a lot of trials I'm really struggling on the following problem:

I would like to extrude a 2D dxf up to a certain height, but not directly in a perfect Z-direction but in a certain angle to get a sloped 3D shape. The targeted 3D object is a height of 10mm with a ceratin angular. Hull command is not working because the dxfs have a defined hole shape inside. If anybody has an idea how to solve this issue, please give ma a hint.

A trial with 'rotate' before extruding (after extruding I planned to rotate backwards) is interpreted in no real rotation but in extruding the plane shadow (light from above) into Z direction.

  linear_extrude(20,scale=[1,1])
                scale([1,1])
                rotate([45,0,45])
                translate([0,0,0])
                circle(50, $fa=1);

best regards Sven

Something like this?

a=15;
hull()
{
cylinder(r=50, h=0.001);
translate([0,0,20])
rotate([a,0,0])
scale([1,1/cos(a)])
cylinder(r=50, h=0.001);
}

Hull works on circles on the x and y axes, but not on the z axis for some reason.

No - something like this , but it should be without hull(). If I use hull() I have to take it 350 times for my application for linear_extrude, and hull() is a very time intensive function. Additionally hull() fills everything in the inner, which is not useful.

a=0;
hull()
{
cylinder(r=50, h=0.001);
translate([15,0,20])
rotate([a,0,0])
scale([1,1/cos(a)])
cylinder(r=50, h=0.001);
}

hope this helps you out
```
    skewx=1;
    skewy=1;
    M=[
    [1, 0, skewx, 0],
    [0, 1, skewy, 0],
    [ 0, 0, 1, 0],
    [ 0, 0, 0,  1]
                  ];
    multmatrix(M)
    linear_extrude(10)
    yourshape();

    module yourshape(){
        union(){
        circle(10);
        square(15);
        }
    }
```