On Fri, Sep 07, 2018 at 10:47:15AM +0100, nop head wrote:

> >Is there a simple way to get a cube at the origin with it's corners on the

> axes?

>

> No it is physically impossible.

Technically correct, but

rotate ([0,atan (sqrt(2)),0])

rotate ([0,0,45])

cube (40, center=true);

is what he was asking for.... I think.

Roger.

>

> On 7 September 2018 at 10:06, Aurum <

[hidden email]> wrote:

>

> > Having now subscribed to the mailing list hopefully this will now be

> > posted.

> > Sorry if it's posted twice.

> >

> > What I'm trying to do is understand how to get a cube at the origin with

> > it's corners on the axes.

> >

> > Firstly, I tried rotating by 45° about x and y with no success.

> >

> > I then rotated 45° about the X axis with

> > rotate(45,[1,0,0]){

> > color("cyan") cube(10,center=true);

> > }

> > and looked down the Y axis. What I see is this.

> > <

http://forum.openscad.org/file/t2335/cube1.png>

> >

> > I now realize that I'm not looking at a square anymore but a rectangle with

> > sides 10 and 14.14 (10 x root 2) and so to align the corners with the Z

> > axis

> > I need to rotate by atan(1.414) = 54.7°.

> >

> > I do this with

> > rotate(45,[1,0,0]){

> > rotate(54.7,[0,1,0]){

> > color("cyan") cube(10,center=true);

> > }

> > }

> > and the result is

> > <

http://forum.openscad.org/file/t2335/cube2.png>

> >

> > What am I doing wrong?

> >

> > Is there a simple way to get a cube at the origin with it's corners on the

> > axes?

> >

> > Mike.

> >

> >

> >

> > --

> > Sent from:

http://forum.openscad.org/> >

> > _______________________________________________

> > OpenSCAD mailing list

> >

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> >

http://lists.openscad.org/mailman/listinfo/discuss_lists.openscad.org> >

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